What is the domain of f(x)=ln(1+x^2) ?

The domain of f(x)=ln(1+x^2) is -infinity <x<infinity

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domain of f(x)=ln(1+x^2)

domain

f (x) = ln (1 + x^{2})

- \infty < x < \infty

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{( 2 x ^{2} - 6 x + 4 )}{- 3 x - 5}

1.5 - 3 x

f (x) = x - \frac{4}{x}

y = \frac{1}{x - 3}

f (x) = x + ln (x^{2} - 3)

What is the domain of f(x)=ln(1+x^2) ?
The domain of f(x)=ln(1+x^2) is -infinity <x<infinity