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Frequently Asked Questions (FAQ)
What is the inverse of f(x)=((x^5)/7)^{1/7}-1 ?
- The inverse of f(x)=((x^5)/7)^{1/7}-1 is \sqrt[5]{7x^7+49x^6+147x^5+245x^4+245x^3+147x^2+49x+7}