What is the inverse of f(x)=sqrt((1-3x)/2) ?

The inverse of f(x)=sqrt((1-3x)/2) is -(2x^2-1)/3

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inverse of f(x)=sqrt((1-3x)/2)

inverse

f (x) = \frac{1 - 3 x}{2}

- \frac{2 x ^{2} - 1}{3}

Solution steps

y = \frac{1 - 3 x}{2}

Replace

x

with

y

x = \frac{1 - 3 y}{2}

Solve for

y, x = \frac{1 - 3 y}{2}

- \frac{2 x ^{2} - 1}{3}

2^{x} - 3

f (x) = \frac{5 x}{2 x - 3}

- (2)^{- \frac{14}{25} (x - 21)} + 25

f (x) = \frac{3 x - 1}{2 x + 1}

f (x) = 2 - x + 3

What is the inverse of f(x)=sqrt((1-3x)/2) ?
The inverse of f(x)=sqrt((1-3x)/2) is -(2x^2-1)/3