What is the range of 1/(sqrt(1-x^2)) ?

The range of 1/(sqrt(1-x^2)) is f(x)>= 1

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range of 1/(sqrt(1-x^2))

range

\frac{1}{1 - x ^{2}}

f (x) \geq 1

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{1}{1 - x ^{2}} : - 1 < x < 1

Extreme Points of

\frac{1}{1 - x ^{2}} :

Minimum

(0, 1)

Find the range for the interval

- 1 < x < 1 : 1 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq 1

\frac{2 x ^{2} - 12 x + 16}{x ^{2} - x - 12}

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\frac{x ^{3}}{3} - 3 x^{2} - 7 x

9 x - 6 y = - 6