What is the inverse of f(x)=(2a^3)/(17) ?

The inverse of f(x)=(2a^3)/(17) is cube root of (17a)/2

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inverse of f(x)=(2a^3)/(17)

inverse

f (x) = \frac{2 a ^{3}}{17}

3 \frac{17 a}{2}

Solution steps

y = \frac{2 a ^{3}}{17}

Replace

a

with

y

a = \frac{2 y ^{3}}{17}

Solve for

y, a = \frac{2 y ^{3}}{17}

3 \frac{17 a}{2}

cr i t i c a l \frac{9 x}{16 - x ^{2}}

in v erse f (x) = (x^{7} - 9)^{9}

in f l ec t i o n (x - 4)^{3}

e x t re m e (x - 5)^{\frac{2}{3}}

p a r i t y f (x) = \frac{tan ( x )}{4 - x ^{2}}

What is the inverse of f(x)=(2a^3)/(17) ?
The inverse of f(x)=(2a^3)/(17) is cube root of (17a)/2