What is the inverse of f(x)=(x^7-9)^9 ?

The inverse of f(x)=(x^7-9)^9 is \sqrt[7]{\sqrt[9]{x}+9}

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inverse of f(x)=(x^7-9)^9

inverse

f (x) = (x^{7} - 9)^{9}

7 9 x + 9

Solution steps

y = (x^{7} - 9)^{9}

Replace

x

with

y

x = (y^{7} - 9)^{9}

Solve for

y, x = (y^{7} - 9)^{9}

7 9 x + 9

in f l ec t i o n (x - 4)^{3}

e x t re m e (x - 5)^{\frac{2}{3}}

p a r i t y f (x) = \frac{tan ( x )}{4 - x ^{2}}

d o main f (x) = 0. 5^{x}

d o main f (x) = \frac{2 x ^{2} - 3}{5}

What is the inverse of f(x)=(x^7-9)^9 ?
The inverse of f(x)=(x^7-9)^9 is \sqrt[7]{\sqrt[9]{x}+9}