What is the domain of y= 7/(sqrt(1+t)) ?

The domain of y= 7/(sqrt(1+t)) is t>-1

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domain of y= 7/(sqrt(1+t))

domain

y = \frac{7}{1 + t}

t > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 1

Find undefined (singularity) points:

t = - 1

Combine real regions and undefined points for final function domain

t > - 1

p a r i t y f (x) = \frac{1}{2} x^{2} - 2 x

m o n o t o n e - 2 x^{2} - 2 x - 2

in v erse f (x) = - \frac{1}{5} x - 7

a sy m pt o t es \frac{x ^{2} + x - 6}{x - 3}

a sy m pt o t es f (x) = \frac{( x ^{2} - x )}{x ^{2} - 3 x + 2}