What is the asymptotes of f(x)=((x^2-x))/(x^2-3x+2) ?

The asymptotes of f(x)=((x^2-x))/(x^2-3x+2) is Vertical: x=2,Horizontal: y=1

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asymptotes of f(x)=((x^2-x))/(x^2-3x+2)

asymptotes

f (x) = \frac{( x ^{2} - x )}{x ^{2} - 3 x + 2}

Vertical : x = 2, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - x}{x ^{2} - 3 x + 2} : x = 2

Horizontal Asymptotes of

\frac{x ^{2} - x}{x ^{2} - 3 x + 2} : y = 1

Slant Asymptotes of

\frac{x ^{2} - x}{x ^{2} - 3 x + 2} :

None

Vertical : x = 2, Horizontal : y = 1

f (x) = 2 x^{3} + 3 x^{2} - 1

f (x) = \frac{1}{[ x + 3 ]}

f (x) = - x^{4} - 3 x^{3} + 8 x + 8

y = ln (x) + 7

f (x) = 2.5 sin (2 x)

What is the asymptotes of f(x)=((x^2-x))/(x^2-3x+2) ?
The asymptotes of f(x)=((x^2-x))/(x^2-3x+2) is Vertical: x=2,Horizontal: y=1