What is the extreme f(x)=x^3-75x+5 ?

The extreme f(x)=x^3-75x+5 is Maximum(-5,255),Minimum(5,-245)

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extreme f(x)=x^3-75x+5

extreme points

f (x) = x^{3} - 75 x + 5

Maximum (- 5, 255), Minimum (5, - 245)

Solution steps

f^{'} (x) = 3 x^{2} - 75

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

x^{3} - 75 x + 5 : 255

Maximum (- 5, 255)

Plug

x = 5

into

x^{3} - 75 x + 5 : - 245

Minimum (5, - 245)

Maximum (- 5, 255), Minimum (5, - 245)

f (x) = \frac{3 x + 2}{x - 5}

f (x) = \frac{x}{2} + 5

f (x) = - 2 x^{5} + 7 x^{3}

f (x) = x^{3} - 64

(- 4, 3), (2, - 5)

What is the extreme f(x)=x^3-75x+5 ?
The extreme f(x)=x^3-75x+5 is Maximum(-5,255),Minimum(5,-245)