What is the slope of y=(-2xy)/(x^2+4),\at x=2 ?

The slope of y=(-2xy)/(x^2+4),\at x=2 is m=0

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slope of y=(-2xy)/(x^2+4),\at x=2

slope

y = \frac{- 2 x y}{x ^{2} + 4}, at x = 2

m = 0

Solution steps

y = \frac{- 2 x y}{x ^{2} + 4}

Isolate

y

for

y = \frac{- 2 x y}{x ^{2} + 4} : y = 0; x \neq = 2 i, x \neq = - 2 i

Rewrite as

y = 0 x + 0

For a line equation for the form of

y = mx + b

, the slope is

m

m = 0

y - 3 = 4 (x + 8)

(1) (1)

f (x) = - x + 2 y = 6

f (x) = 3 x^{2} + x - 2

f (x) = \frac{6 + x}{7 - x}

What is the slope of y=(-2xy)/(x^2+4),\at x=2 ?
The slope of y=(-2xy)/(x^2+4),\at x=2 is m=0