What is the domain of f(x)=sqrt(t+1) ?

The domain of f(x)=sqrt(t+1) is t>=-1

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domain of f(x)=sqrt(t+1)

domain

f (x) = t + 1

t \geq - 1

Interval Notation

Solution steps

Find non-negative values for radicals:

t \geq - 1

The function domain

t \geq - 1

f (x) = \frac{x}{x ( x + 6 )}

f (x) = x + 2

f (x) = x^{2} - 4 x + 8

3 x + 5 y = 15

\frac{2}{x + 1}