What is the perpendicular 3x-4y=15 ?

The perpendicular 3x-4y=15 is y=-4/3 x+b

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perpendicular 3x-4y=15

perpendicular

3 x - 4 y = 15

y = - \frac{4}{3} x + b

Solution steps

Find the slope of

3 x - 4 y = 15 : m = \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = - \frac{4}{3}

Line with slope m=

- \frac{4}{3} : y = - \frac{4}{3} x + b

y = - \frac{4}{3} x + b

d o main f (x) = \frac{7 - x}{x ^{2} + 1}

d o main \frac{1}{x ^{2} + 4}

p a r i t y 2 - \frac{3}{x}

e x t re m e f (x) = x^{6} e^{x} - 3

d o main y = \frac{x ^{3}}{( x - 1 ) ^{2}}