What is the domain of 1/(sqrt(x^2-5x)) ?

The domain of 1/(sqrt(x^2-5x)) is x 5

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domain of 1/(sqrt(x^2-5x))

domain

\frac{1}{x ^{2} - 5 x}

x < 0 or x > 5

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 5

Find undefined (singularity) points:

x = 5, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 5

f (x) = (4 x - 1)^{3}

5^{x}

f (x) = - 2 x^{2} + 8 x - 10

f (x) = x x - 1

\frac{x ^{2} + 2 x}{2 x ^{3} - 3 x ^{2} - 2 x}

What is the domain of 1/(sqrt(x^2-5x)) ?
The domain of 1/(sqrt(x^2-5x)) is x<0\lor x>5