What is the critical (x^2-x)/(x^2-4x+3) ?

The critical (x^2-x)/(x^2-4x+3) is None

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critical (x^2-x)/(x^2-4x+3)

critical points

\frac{x ^{2} - x}{x ^{2} - 4 x + 3}

None

Solution steps

\frac{x ^{2} - x}{x ^{2} - 4 x + 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - x}{x ^{2} - 4 x + 3} : x < 1 or 1 < x < 3 or x > 3

\frac{x ^{2} - x}{x ^{2} - 4 x + 3}

is not defined at

x = 3

, therefore:

None

(- 2, 1), (4, 3)

- x^{2} + 6 x + 1

3 x^{\frac{2}{3}} - x

f (x) = 6 x - 18

(4.4) (5.5)

What is the critical (x^2-x)/(x^2-4x+3) ?
The critical (x^2-x)/(x^2-4x+3) is None