What is the domain of y=sqrt(x^2-16) ?

The domain of y=sqrt(x^2-16) is x = 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=sqrt(x^2-16)

domain

y = x^{2} - 16

x \leq - 4 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

The function domain

x \leq - 4 or x \geq 4

f (x) = \frac{2 x + 5}{x - 7}

(- 3, 4), (2, - 6)

f (x) = \frac{x}{9 - x ^{2}}

(- 5, - 8), (- 8, 7)

\frac{1}{4} x^{2} + \frac{2}{3} x - \frac{1}{6}

What is the domain of y=sqrt(x^2-16) ?
The domain of y=sqrt(x^2-16) is x<=-4\lor x>= 4