What is the domain of f(x)= x/(sqrt(9-x^2)) ?

The domain of f(x)= x/(sqrt(9-x^2)) is -3<x<3

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domain of f(x)= x/(sqrt(9-x^2))

domain

f (x) = \frac{x}{9 - x ^{2}}

- 3 < x < 3

Interval Notation

(- 3, 3)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x < 3

(- 5, - 8), (- 8, 7)

\frac{1}{4} x^{2} + \frac{2}{3} x - \frac{1}{6}

f (x) = 2 x + 7

\frac{4}{x} - x

f (x) = \frac{( x ^{2} - 4 x )}{x ^{2} - 16}

What is the domain of f(x)= x/(sqrt(9-x^2)) ?
The domain of f(x)= x/(sqrt(9-x^2)) is -3<x<3