What is the asymptotes of f(x)=((x^2+x+2))/(x-1) ?

The asymptotes of f(x)=((x^2+x+2))/(x-1) is Vertical: x=1,Slant: y=x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

asymptotes of f(x)=((x^2+x+2))/(x-1)

asymptotes

f (x) = \frac{( x ^{2} + x + 2 )}{x - 1}

Vertical : x = 1, Slant : y = x + 2

Solution steps

Vertical asymptotes of

\frac{x ^{2} + x + 2}{x - 1} : x = 1

Horizontal Asymptotes of

\frac{x ^{2} + x + 2}{x - 1} :

None

Slant Asymptotes of

\frac{x ^{2} + x + 2}{x - 1} : y = x + 2

Vertical : x = 1, Slant : y = x + 2

sy mm e t ry (x - 1)^{2} + 2

d o main f (x) = x + x + 1

r an g e \frac{x + 1}{10 ( x - 2 )}

d i s t an ce (- 1, 2), (3, 2)

d o main f (x) = \frac{3 x ^{2}}{x ^{2} - 4}

What is the asymptotes of f(x)=((x^2+x+2))/(x-1) ?
The asymptotes of f(x)=((x^2+x+2))/(x-1) is Vertical: x=1,Slant: y=x+2