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symmetry
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domain of f(x)=x+sqrt(x)+1range of (x+1)/(10(x-2))distance (-1,2),(3,2)domain of f(x)=(3x^2)/(x^2-4)critical (x^2)/(1-x)
Frequently Asked Questions (FAQ)
What is the symmetry (x-1)^2+2 ?
The symmetry (x-1)^2+2 is x=1