What is the inverse of f(x)=((x+19))/((x-17)) ?

The inverse of f(x)=((x+19))/((x-17)) is (19+17x)/(x-1)

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inverse of f(x)=((x+19))/((x-17))

inverse

f (x) = \frac{( x + 19 )}{( x - 17 )}

\frac{19 + 17 x}{x - 1}

Solution steps

y = \frac{x + 19}{x - 17}

Replace

x

with

y

x = \frac{y + 19}{y - 17}

Solve for

y, x = \frac{y + 19}{y - 17}

\frac{19 + 17 x}{x - 1}

d o main f (x) = - \frac{1}{2 x ^{\frac{3}{2}}}

in v erse y = (x - 2)^{2}

in f l ec t i o n f (x) = 2 x (x + 2)^{2}

e x t re m e f (x) = x^{3} - 4 x^{2} + 4 x + 1

in t erce pt s f (x) = - 2

What is the inverse of f(x)=((x+19))/((x-17)) ?
The inverse of f(x)=((x+19))/((x-17)) is (19+17x)/(x-1)