What is the domain of f(x)=-1/(2x^{3/2)} ?

The domain of f(x)=-1/(2x^{3/2)} is x>0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=-1/(2x^{3/2)}

domain

f (x) = - \frac{1}{2 x ^{\frac{3}{2}}}

x > 0

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

f (x) = (x - 4)^{2} - 5

y = (x - 2)^{2}

f (x) = 2 x (x + 2)^{2}

f (x) = x^{3} - 4 x^{2} + 4 x + 1

f (x) = - 2

What is the domain of f(x)=-1/(2x^{3/2)} ?
The domain of f(x)=-1/(2x^{3/2)} is x>0