What is the domain of x/(\sqrt[4]{36-x^2)} ?

The domain of x/(\sqrt[4]{36-x^2)} is -6<x<6

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domain of x/(\sqrt[4]{36-x^2)}

domain

\frac{x}{4 36 - x ^{2}}

- 6 < x < 6

Interval Notation

(- 6, 6)

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 6

Find undefined (singularity) points:

x = 6, x = - 6

Combine real regions and undefined points for final function domain

- 6 < x < 6

d o main f (x) = \frac{1}{x + 18}

a sy m pt o t es f (x) = 10

in t erce pt s f (x) = x^{2} - 2 x - 15

in v erse y = - 2 x^{2} + 8 x - 7

r an g e \frac{4}{3 - x}

What is the domain of x/(\sqrt[4]{36-x^2)} ?
The domain of x/(\sqrt[4]{36-x^2)} is -6<x<6