What is the inverse of y=-2x^2+8x-7 ?

The inverse of y=-2x^2+8x-7 is -(-8+sqrt(-8x+8))/4 ,-(-8-sqrt(-8x+8))/4

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inverse of y=-2x^2+8x-7

inverse

y = - 2 x^{2} + 8 x - 7

- \frac{- 8 + - 8 x + 8}{4}, - \frac{- 8 - - 8 x + 8}{4}

Solution steps

y = - 2 x^{2} + 8 x - 7

Replace

x

with

y

x = - 2 y^{2} + 8 y - 7

Solve for

y, x = - 2 y^{2} + 8 y - 7

- \frac{- 8 + - 8 x + 8}{4}, - \frac{- 8 - - 8 x + 8}{4}

\frac{4}{3 - x}

f (x) = \frac{6}{x ^{2}}

2 x + 7 y = 14

f (x) = \frac{( x - 7 )}{( x - 4 ) ( x + 3 )}

\frac{x - 9}{x - 3}

What is the inverse of y=-2x^2+8x-7 ?
The inverse of y=-2x^2+8x-7 is -(-8+sqrt(-8x+8))/4 ,-(-8-sqrt(-8x+8))/4