What is the inverse of f(x)=(e^x-e^{-x})/2 ?

The inverse of f(x)=(e^x-e^{-x})/2 is ln(x+sqrt(x^2+1)),ln(x-sqrt(x^2+1))

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inverse of f(x)=(e^x-e^{-x})/2

inverse

f (x) = \frac{e ^{x} - e ^{- x}}{2}

ln (x + x^{2} + 1), ln (x - x^{2} + 1)

Solution steps

y = \frac{e ^{x} - e ^{- x}}{2}

Replace

x

with

y

x = \frac{e ^{y} - e ^{- y}}{2}

Solve for

y, x = \frac{e ^{y} - e ^{- y}}{2}

ln (x + x^{2} + 1), ln (x - x^{2} + 1)

f (x) = 5 x^{2} - 38 x - 63

\frac{x ^{2}}{( x + 2 ) ( x - 3 )}

\frac{4}{x + 3}

y = \frac{8 x + 1}{x - 8}

ln (x) 14.4177000000000 \dots

What is the inverse of f(x)=(e^x-e^{-x})/2 ?
The inverse of f(x)=(e^x-e^{-x})/2 is ln(x+sqrt(x^2+1)),ln(x-sqrt(x^2+1))