What is the critical (x+1)(x-4)^2 ?

The critical (x+1)(x-4)^2 is x= 2/3 ,x=4

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critical (x+1)(x-4)^2

critical points

(x + 1) (x - 4)^{2}

x = \frac{2}{3}, x = 4

Solution steps

(x + 1) (x - 4)^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{2}{3}, x = 4

Identify critical points not in

f (x)

domain

Domain of

(x + 1) (x - 4)^{2} : - \infty < x < \infty

All critical points are in domain

x = \frac{2}{3}, x = 4

f (x) = \frac{( x + 19 )}{( x - 18 )}

\frac{2}{x + 1} + \frac{x}{x + 1}

x^{3} - 3 x^{2} + 2 x + 1

\frac{1}{3} lo g_{10} (3 x)

(- 7, 5), (7, 3)