What is the perpendicular 2x+7y=1,(1,7) ?

The perpendicular 2x+7y=1,(1,7) is y= 7/2 x+7/2

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perpendicular 2x+7y=1,(1,7)

perpendicular

2 x + 7 y = 1, (1, 7)

y = \frac{7}{2} x + \frac{7}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

2 x + 7 y = 1

that passes through

(1, 7)

Find the slope of

2 x + 7 y = 1 : m = - \frac{2}{7}

Compute the slope of the perpendicular line:

m_{p} = \frac{7}{2}

Find the line with slope m=

\frac{7}{2}

and passing through

(1, 7) : y = \frac{7}{2} x + \frac{7}{2}

y = \frac{7}{2} x + \frac{7}{2}

s im pl i f y (2.5) (- 1.7)

sy mm e t ry x^{2} - 4 x + 4

cr i t i c a l f (x) = - 1 + 4 x - x^{3}

e x t re m e f (x) = x + \frac{17}{x}

d i s t an ce (8, 6), (- 4, - 3)

What is the perpendicular 2x+7y=1,(1,7) ?
The perpendicular 2x+7y=1,(1,7) is y= 7/2 x+7/2