What is the extreme f(x)=x+(17)/x ?

The extreme f(x)=x+(17)/x is Maximum(-sqrt(17),-2sqrt(17)),Minimum(sqrt(17),2sqrt(17))

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extreme f(x)=x+(17)/x

extreme points

f (x) = x + \frac{17}{x}

Maximum (- 17, - 217), Minimum (17, 217)

Solution steps

f^{'} (x) = 1 - \frac{17}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 17,

Decreasing

: - 17 < x < 0,

Decreasing

: 0 < x < 17,

Increasing

: 17 < x < \infty

Plug

x = - 17

into

x + \frac{17}{x} : - 217

Maximum (- 17, - 217)

Plug

x = 17

into

x + \frac{17}{x} : 217

Minimum (17, 217)

Maximum (- 17, - 217), Minimum (17, 217)

d i s t an ce (8, 6), (- 4, - 3)

a sy m pt o t es f (x) = \frac{- x ^{2} - 5 x + 2}{x + 3}

l in e - x + y = 4

in v erse f (x) = \frac{( x - 6 ) ^{\frac{1}{2}}}{7}

r an g e f (x) = 2 (x + 3)^{2} - 1

What is the extreme f(x)=x+(17)/x ?
The extreme f(x)=x+(17)/x is Maximum(-sqrt(17),-2sqrt(17)),Minimum(sqrt(17),2sqrt(17))