What is the extreme f(x)=(x^2-9)^3 ?

The extreme f(x)=(x^2-9)^3 is Saddle(-3,0),Minimum(0,-729),Saddle(3,0)

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extreme f(x)=(x^2-9)^3

extreme points

f (x) = (x^{2} - 9)^{3}

Saddle (- 3, 0), Minimum (0, - 729), Saddle (3, 0)

Solution steps

f^{'} (x) = 6 x (x^{2} - 9)^{2}

Find intervals:

Decreasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 0,

Increasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

(x^{2} - 9)^{3} : 0

Saddle (- 3, 0)

Plug

x = 0

into

(x^{2} - 9)^{3} : - 729

Minimum (0, - 729)

Plug

x = 3

into

(x^{2} - 9)^{3} : 0

Saddle (3, 0)

Saddle (- 3, 0), Minimum (0, - 729), Saddle (3, 0)

f (x) = \frac{4 sec ( x ) - 4}{x ^{2}}

f (x) = x + 6

4 x - 8

y = 3 x - 2, (2, - 4)

f (x) = \frac{5}{9} (x - 32), x \geq - 459.6

What is the extreme f(x)=(x^2-9)^3 ?
The extreme f(x)=(x^2-9)^3 is Saddle(-3,0),Minimum(0,-729),Saddle(3,0)