What is the perpendicular Y(x)=3x+9,(-2,3) ?

The perpendicular Y(x)=3x+9,(-2,3) is y=-1/3 x+7/3

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perpendicular Y(x)=3x+9,(-2,3)

perpendicular

Y (x) = 3 x + 9, (- 2, 3)

y = - \frac{1}{3} x + \frac{7}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

Y (x) = 3 x + 9

that passes through

(- 2, 3)

Find the slope of

Y (x) = 3 x + 9 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(- 2, 3) : y = - \frac{1}{3} x + \frac{7}{3}

y = - \frac{1}{3} x + \frac{7}{3}

f (x) = 8 x - 2

f (x) = 9 x - 7

f (x) = \frac{x ^{2} - 25}{x - 5}

(- 2, - 3), (- 3, 1)

f (x) = - 12 x^{2} + 156 x

What is the perpendicular Y(x)=3x+9,(-2,3) ?
The perpendicular Y(x)=3x+9,(-2,3) is y=-1/3 x+7/3