What is the asymptotes of f(x)=(2x^2)/(x^2-8x+16) ?

The asymptotes of f(x)=(2x^2)/(x^2-8x+16) is Vertical: x=4,Horizontal: y=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

asymptotes of f(x)=(2x^2)/(x^2-8x+16)

asymptotes

f (x) = \frac{2 x ^{2}}{x ^{2} - 8 x + 16}

Vertical : x = 4, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2}}{x ^{2} - 8 x + 16} : x = 4

Horizontal Asymptotes of

\frac{2 x ^{2}}{x ^{2} - 8 x + 16} : y = 2

Slant Asymptotes of

\frac{2 x ^{2}}{x ^{2} - 8 x + 16} :

None

Vertical : x = 4, Horizontal : y = 2

a sy m pt o t es f (x) = \frac{x ^{2} - 3 x - 5}{x + 2}

in v erse \frac{1}{s + 2}

e x t re m e f (x) = x^{4} - 7 x^{2} + 8

s l o p e in t erce pt y - 3 = \frac{5}{3} (x - 6)

d o main f (x) = \frac{6}{16 - x ^{2}}

What is the asymptotes of f(x)=(2x^2)/(x^2-8x+16) ?
The asymptotes of f(x)=(2x^2)/(x^2-8x+16) is Vertical: x=4,Horizontal: y=2