What is the asymptotes of f(x)=(x^2-3x-5)/(x+2) ?

The asymptotes of f(x)=(x^2-3x-5)/(x+2) is Vertical: x=-2,Slant: y=x-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

asymptotes of f(x)=(x^2-3x-5)/(x+2)

asymptotes

f (x) = \frac{x ^{2} - 3 x - 5}{x + 2}

Vertical : x = - 2, Slant : y = x - 5

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 3 x - 5}{x + 2} : x = - 2

Horizontal Asymptotes of

\frac{x ^{2} - 3 x - 5}{x + 2} :

None

Slant Asymptotes of

\frac{x ^{2} - 3 x - 5}{x + 2} : y = x - 5

Vertical : x = - 2, Slant : y = x - 5

in v erse \frac{1}{s + 2}

e x t re m e f (x) = x^{4} - 7 x^{2} + 8

s l o p e in t erce pt y - 3 = \frac{5}{3} (x - 6)

d o main f (x) = \frac{6}{16 - x ^{2}}

e x t re m e f (x) = 8 x^{3} - 6 x + 7

What is the asymptotes of f(x)=(x^2-3x-5)/(x+2) ?
The asymptotes of f(x)=(x^2-3x-5)/(x+2) is Vertical: x=-2,Slant: y=x-5