What is the inverse of f(x)=(x-1)^2-1 ?

The inverse of f(x)=(x-1)^2-1 is sqrt(x+1)+1,-sqrt(x+1)+1

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inverse of f(x)=(x-1)^2-1

inverse

f (x) = (x - 1)^{2} - 1

x + 1 + 1, - x + 1 + 1

Solution steps

y = (x - 1)^{2} - 1

Replace

x

with

y

x = (y - 1)^{2} - 1

Solve for

y, x = (y - 1)^{2} - 1

x + 1 + 1, - x + 1 + 1

e^{3 x} (8 - x)

(- 1, 5), (4, - 3)

4 x^{2} - x + 17

3 x^{3} - 36 x - 5

f (x) = lo g_{10} (\frac{1}{x})

What is the inverse of f(x)=(x-1)^2-1 ?
The inverse of f(x)=(x-1)^2-1 is sqrt(x+1)+1,-sqrt(x+1)+1