What is the inverse of f(x)=sqrt(x^2+6x) ?

The inverse of f(x)=sqrt(x^2+6x) is -3+sqrt(x^2+9),-sqrt(x^2+9)-3

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inverse of f(x)=sqrt(x^2+6x)

inverse

f (x) = x^{2} + 6 x

- 3 + x^{2} + 9, - x^{2} + 9 - 3

Solution steps

y = x^{2} + 6 x

Replace

x

with

y

x = y^{2} + 6 y

Solve for

y, x = y^{2} + 6 y

- 3 + x^{2} + 9, - x^{2} + 9 - 3

p a r i t y f (x) = \frac{1}{x + 9}

in t erce pt s \frac{3 x ^{2} - 14 x - 24}{( x ^{2} + 8 ) ^{2}}

d o main f (x) = x^{3} - x

e x t re m e f (x) = \frac{x}{x - 2}

p er p e n d i c u l a r y = 2 x - 7

What is the inverse of f(x)=sqrt(x^2+6x) ?
The inverse of f(x)=sqrt(x^2+6x) is -3+sqrt(x^2+9),-sqrt(x^2+9)-3