What is the perpendicular y=3x-2,(0,-6) ?

The perpendicular y=3x-2,(0,-6) is y=-1/3 x-6

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perpendicular y=3x-2,(0,-6)

perpendicular

y = 3 x - 2, (0, - 6)

y = - \frac{1}{3} x - 6

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x - 2

that passes through

(0, - 6)

Find the slope of

y = 3 x - 2 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(0, - 6) : y = - \frac{1}{3} x - 6

y = - \frac{1}{3} x - 6

(5.1) (- 3.6)

f (x) = 4 - 25 - x^{2}

y = - 3 x - 10

\frac{- 2 x + 2}{x + 7}

f (x) = x - 3 + x^{2}

What is the perpendicular y=3x-2,(0,-6) ?
The perpendicular y=3x-2,(0,-6) is y=-1/3 x-6