What is the inverse of f(x)=x^2-3x-4 ?

The inverse of f(x)=x^2-3x-4 is (3+sqrt(4x+25))/2 ,(3-sqrt(4x+25))/2

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inverse of f(x)=x^2-3x-4

inverse

f (x) = x^{2} - 3 x - 4

\frac{3 + 4 x + 25}{2}, \frac{3 - 4 x + 25}{2}

Solution steps

y = x^{2} - 3 x - 4

Replace

x

with

y

x = y^{2} - 3 y - 4

Solve for

y, x = y^{2} - 3 y - 4

\frac{3 + 4 x + 25}{2}, \frac{3 - 4 x + 25}{2}

p er p e n d i c u l a r y = 4 x + c

s im pl i f y (5.8) (- 1.6)

in v erse f (x) = (x^{3} - 1)^{7}

a sy m pt o t es x

r an g e \frac{6 x + 7}{x + 6}

What is the inverse of f(x)=x^2-3x-4 ?
The inverse of f(x)=x^2-3x-4 is (3+sqrt(4x+25))/2 ,(3-sqrt(4x+25))/2