What is the inverse of f(x)=(x^3-1)^7 ?

The inverse of f(x)=(x^3-1)^7 is cube root of \sqrt[7]{x}+1

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inverse of f(x)=(x^3-1)^7

inverse

f (x) = (x^{3} - 1)^{7}

3 7 x + 1

Solution steps

y = (x^{3} - 1)^{7}

Replace

x

with

y

x = (y^{3} - 1)^{7}

Solve for

y, x = (y^{3} - 1)^{7}

3 7 x + 1

a sy m pt o t es x

r an g e \frac{6 x + 7}{x + 6}

a sy m pt o t es f (x) = \frac{( x ^{2} + 2 )}{5 x - 2 x ^{2}}

a sy m pt o t es f (x) = \frac{x ^{2} - 5 x - 1}{x - 3}

in v erse f (x) = \frac{3}{x - 1} + 4

What is the inverse of f(x)=(x^3-1)^7 ?
The inverse of f(x)=(x^3-1)^7 is cube root of \sqrt[7]{x}+1