What is the extreme f(x)=x^4-50x^2+11 ?

The extreme f(x)=x^4-50x^2+11 is Minimum(-5,-614),Maximum(0,11),Minimum(5,-614)

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extreme f(x)=x^4-50x^2+11

extreme points

f (x) = x^{4} - 50 x^{2} + 11

Minimum (- 5, - 614), Maximum (0, 11), Minimum (5, - 614)

Solution steps

f^{'} (x) = 4 x^{3} - 100 x

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

x^{4} - 50 x^{2} + 11 : - 614

Minimum (- 5, - 614)

Plug

x = 0

into

x^{4} - 50 x^{2} + 11 : 11

Maximum (0, 11)

Plug

x = 5

into

x^{4} - 50 x^{2} + 11 : - 614

Minimum (5, - 614)

Minimum (- 5, - 614), Maximum (0, 11), Minimum (5, - 614)

(- \frac{1}{2}, \frac{3}{4}), (\frac{7}{2}, - \frac{13}{4})

sin (5 x + \frac{π}{2})

f (x) = 12 - x

2 - x^{2}

y = x^{3} - 2 x^{2} - 4 x + 1

What is the extreme f(x)=x^4-50x^2+11 ?
The extreme f(x)=x^4-50x^2+11 is Minimum(-5,-614),Maximum(0,11),Minimum(5,-614)