What is the domain of y=3+sqrt(x+2) ?

The domain of y=3+sqrt(x+2) is x>=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of y=3+sqrt(x+2)

domain

y = 3 + x + 2

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

in v erse f (x) = \frac{7 - 8 x}{3}

cr i t i c a l f (x) = 2 x + 4

cr i t i c a l \frac{1}{2} x^{3} - 2 x^{2} - 1

cr i t i c a l - x^{3} + 2 x^{2} + 2

r an g e \frac{3 x ^{3} - 30 x + 76}{x ^{2} - 10 x + 25}