What is the domain of f(x)=\sqrt[3]{x+1} ?

The domain of f(x)=\sqrt[3]{x+1} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{x+1}

domain

f (x) = 3 x + 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

in t erce pt s y = 8 x - 18

s l o p e in t erce pt - \frac{1}{2} x + y = 4

f (x) = \frac{x ^{2}}{x ^{2} - 4}

in t erce pt s f (x) = - x^{2} + 8 x + 2

in t erce pt s \frac{3 x}{( x + 2 ) ^{2}}

What is the domain of f(x)=\sqrt[3]{x+1} ?
The domain of f(x)=\sqrt[3]{x+1} is -infinity <x<infinity