What is the inverse of f(x)=x^2-3x ?

The inverse of f(x)=x^2-3x is (3+sqrt(9+4x))/2 ,(3-sqrt(9+4x))/2

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inverse of f(x)=x^2-3x

inverse

f (x) = x^{2} - 3 x

\frac{3 + 9 + 4 x}{2}, \frac{3 - 9 + 4 x}{2}

Solution steps

y = x^{2} - 3 x

Replace

x

with

y

x = y^{2} - 3 y

Solve for

y, x = y^{2} - 3 y

\frac{3 + 9 + 4 x}{2}, \frac{3 - 9 + 4 x}{2}

f (x) = x - \frac{1}{x}

f (x) = 7 x + 2

f (x) = \frac{- 5 x - 10}{x ^{2} + 2 x}

\frac{1 - x}{2 x - 1}

f (x) = \frac{4 + 7 x}{2}

What is the inverse of f(x)=x^2-3x ?
The inverse of f(x)=x^2-3x is (3+sqrt(9+4x))/2 ,(3-sqrt(9+4x))/2