What is the domain of f(x)=sqrt(9x-8) ?

The domain of f(x)=sqrt(9x-8) is x>= 8/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(x)=sqrt(9x-8)

domain

f (x) = 9 x - 8

x \geq \frac{8}{9}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq \frac{8}{9}

The function domain

x \geq \frac{8}{9}

4 - (x - 2)^{2}

f (x) = x^{3} - 7 x^{2} + 15 x + 9

\frac{x ^{2}}{x}

f (x) = \frac{x ^{2} + 5 x - 6}{x + 3}

\frac{2 x ( x - 1 ) ^{2}}{( x + 1 ) ^{3}}

What is the domain of f(x)=sqrt(9x-8) ?
The domain of f(x)=sqrt(9x-8) is x>= 8/9