What is the domain of-1-7/(x^2-9) ?

The domain of-1-7/(x^2-9) is x 3

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domain of-1-7/(x^2-9)

domain

- 1 - \frac{7}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

y = x^{4} + x^{2} - 4 x + 4

f (x) = \frac{x + 7}{x + 1}

2 x - 1

(12, 5), (10, - 7)

f (x) = \frac{x ^{2}}{( x - 2 ) ^{3}}

What is the domain of-1-7/(x^2-9) ?
The domain of-1-7/(x^2-9) is x<-3\lor-3<x<3\lor x>3