What is the domain of f(x)= 2/(sqrt(4x-3)) ?

The domain of f(x)= 2/(sqrt(4x-3)) is x> 3/4

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domain of f(x)= 2/(sqrt(4x-3))

domain

f (x) = \frac{2}{4 x - 3}

x > \frac{3}{4}

Solution steps

Find non-negative values for radicals:

x \geq \frac{3}{4}

Find undefined (singularity) points:

x = \frac{3}{4}

Combine real regions and undefined points for final function domain

x > \frac{3}{4}

f (x) = \frac{4 x}{2 x + 3}

\frac{x - 2}{2 x ^{4} - x ^{3} + 4 x - 3}

f (x) = 5 x - 2

- 6 x + 3 y = - 9

x^{3} - 24 x^{2} + 144 x + 3

What is the domain of f(x)= 2/(sqrt(4x-3)) ?
The domain of f(x)= 2/(sqrt(4x-3)) is x> 3/4