What is the inverse of y=5x-x^2 ?

The inverse of y=5x-x^2 is -(-5+sqrt(25-4x))/2 ,-(-5-sqrt(25-4x))/2

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inverse of y=5x-x^2

inverse

y = 5 x - x^{2}

- \frac{- 5 + 25 - 4 x}{2}, - \frac{- 5 - 25 - 4 x}{2}

Solution steps

y = 5 x - x^{2}

Replace

x

with

y

x = 5 y - y^{2}

Solve for

y, x = 5 y - y^{2}

- \frac{- 5 + 25 - 4 x}{2}, - \frac{- 5 - 25 - 4 x}{2}

f (x) = \frac{4}{5} x + 2

4 (x - 5)^{\frac{2}{3}}

f (x) = x + 4 - \frac{1 - x}{x}

f (x) = a x^{2}

What is the inverse of y=5x-x^2 ?
The inverse of y=5x-x^2 is -(-5+sqrt(25-4x))/2 ,-(-5-sqrt(25-4x))/2