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Popular >

inflection y=-1/3 x^3+2x^2-1

Solution

inflection points

y = - \frac{1}{3} x^{3} + 2 x^{2} - 1

Solution

(2, \frac{13}{3})

Solution steps

f^{''} (x) = - 2 x + 4

Find intervals:

Concave Upward

: - \infty < x < 2,

Concave Downward

: 2 < x < \infty

Plug

x = 2

into

- \frac{1}{3} x^{3} + 2 x^{2} - 1 : \frac{13}{3}

(2, \frac{13}{3})

Popular Examples

critical y=(x-2)^3 critical points

y = (x - 2)^{3}

inverse of f(x)=x^2-36 inverse

f (x) = x^{2} - 36

domain of f(x)=e^{-x}+2 domain

f (x) = e^{- x} + 2

intercepts of 2(x+3)^2-2 intercepts

2 (x + 3)^{2} - 2

extreme-6x^3+3x^2+12x-2 extreme points

- 6 x^{3} + 3 x^{2} + 12 x - 2

Frequently Asked Questions (FAQ)

What is the inflection y=-1/3 x^3+2x^2-1 ?
The inflection y=-1/3 x^3+2x^2-1 is (2, 13/3)