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Popular >

extreme f(x)=-2x^2-3x+4

Solution

extreme points

f (x) = - 2 x^{2} - 3 x + 4

Solution

Maximum (- \frac{3}{4}, \frac{41}{8})

Solution steps

f^{'} (x) = - 4 x - 3

Find intervals:

Increasing

: - \infty < x < - \frac{3}{4},

Decreasing

: - \frac{3}{4} < x < \infty

Plug

x = - \frac{3}{4}

into

- 2 x^{2} - 3 x + 4 : \frac{41}{8}

Maximum (- \frac{3}{4}, \frac{41}{8})

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extreme f(x,y)=4y^3x^2-12y^2-36y+2 extreme points

f (x, y) = 4 y^{3} x^{2} - 12 y^{2} - 36 y + 2

extreme f(x)=4x^2+5x-2 extreme points

f (x) = 4 x^{2} + 5 x - 2

extreme f(x)=x^5+3x^4-2x+1 extreme points

f (x) = x^{5} + 3 x^{4} - 2 x + 1

extreme f(x)=-2x^3+39x^2-240,4<= x<= 9 extreme points

f (x) = - 2 x^{3} + 39 x^{2} - 240, 4 \leq x \leq 9

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2x^2-3x+4 ?
The extreme f(x)=-2x^2-3x+4 is Maximum(-3/4 , 41/8)