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Frequently Asked Questions (FAQ)
What is the extreme f(x)=x^3e^{-4x},0<= x<= 2 ?
- The extreme f(x)=x^3e^{-4x},0<= x<= 2 is Minimum(0,0),Maximum(3/4 ,(27)/(64e^3)),Minimum(2, 8/(e^8))