extreme-0.015x^2+1.24x-7.4

Lösung

extrempunkte

- 0.015 x^{2} + 1.24 x - 7.4

Maximum (\frac{124}{3}, 18.22666 \dots)

Schritte zur Lösung

f^{'} (x) = - 0.03 x + 1.24

Intervalle finden:

Ansteigend

: - \infty < x < \frac{124}{3},

Absteigend

: \frac{124}{3} < x < \infty

Stecke

x = \frac{124}{3}

- 0.015 x^{2} + 1.24 x - 7.4 : 18.22666 \dots

Maximum (\frac{124}{3}, 18.22666 \dots)

e x t re m e f (x, y) = x^{2} + y^{2} - 10 x + 16 y - 6

e x t re m e f (x) = \frac{x ^{4}}{4} - (\frac{x}{3})^{3} - x^{2} + 1

e x t re m e f (x) = cos (x) - 9 x, 0 \leq x \leq 4 π

e x t re m e y = x e^{- \frac{x ^{2}}{18}}

e x t re m e f (x) = \frac{8 - 9 x}{3 x + 3}