What is the extreme f(x)=(15x^2-2x-7)/(-5x-1)y ?

The extreme f(x)=(15x^2-2x-7)/(-5x-1)y is Saddle((1+sqrt(106))/(15),0),Saddle((1-sqrt(106))/(15),0)

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extreme f(x)=(15x^2-2x-7)/(-5x-1)y

extreme points

f (x) = \frac{15 x ^{2} - 2 x - 7}{- 5 x - 1} y

Saddle (\frac{1 + 106}{15}, 0), Saddle (\frac{1 - 106}{15}, 0)

Solution steps

Find the critical points:

(\frac{1 + 106}{15}, 0), (\frac{1 - 106}{15}, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - \frac{( - 75 x ^{2} - 30 x - 33 ) ^{2}}{( - 5 x - 1 ) ^{4}}

Check the sign of at each critical point

Check critical point

(\frac{1 + 106}{15}, 0) :

Saddle

Check critical point

(\frac{1 - 106}{15}, 0) :

Saddle

Saddle (\frac{1 + 106}{15}, 0), Saddle (\frac{1 - 106}{15}, 0)

f (x) = e^{x^{2}} (x^{2} - 5) + 8

f (x) = 2 + 5 e^{- 0.1 x}

\frac{3 x}{5 - x}

f (x) = x^{3} + 9 x^{2} + 15 x + 1

- 0.001 x^{2} + 4.6 x - 90

What is the extreme f(x)=(15x^2-2x-7)/(-5x-1)y ?
The extreme f(x)=(15x^2-2x-7)/(-5x-1)y is Saddle((1+sqrt(106))/(15),0),Saddle((1-sqrt(106))/(15),0)