What is the extreme f(x)= 4/3 x^3-13/2 x^2-3x+11 ?

The extreme f(x)= 4/3 x^3-13/2 x^2-3x+11 is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)= 4/3 x^3-13/2 x^2-3x+11

extreme points

f (x) = \frac{4}{3} x^{3} - \frac{13}{2} x^{2} - 3 x + 11

Maximum (\frac{13 - 217}{8}, \frac{217 217 - 3133}{192} + 11), Minimum (\frac{13 + 217}{8}, \frac{- 3133 - 217 217}{192} + 11)

Solution steps

f^{'} (x) = 4 x^{2} - 13 x - 3

Find intervals:

Increasing

: - \infty < x < \frac{- 217 + 13}{8},

Decreasing

: \frac{- 217 + 13}{8} < x < \frac{217 + 13}{8},

Increasing

: \frac{217 + 13}{8} < x < \infty

Plug

x = \frac{13 - 217}{8}

into

\frac{4}{3} x^{3} - \frac{13}{2} x^{2} - 3 x + 11 : \frac{217 217 - 3133}{192} + 11

Maximum (\frac{13 - 217}{8}, \frac{217 217 - 3133}{192} + 11)

Plug

x = \frac{13 + 217}{8}

into

\frac{4}{3} x^{3} - \frac{13}{2} x^{2} - 3 x + 11 : \frac{- 3133 - 217 217}{192} + 11

Minimum (\frac{13 + 217}{8}, \frac{- 3133 - 217 217}{192} + 11)

Maximum (\frac{13 - 217}{8}, \frac{217 217 - 3133}{192} + 11), Minimum (\frac{13 + 217}{8}, \frac{- 3133 - 217 217}{192} + 11)

f (x) = 3 x^{3} - 14 x + 20 x - 8

f (x) = (2 x^{2} - 5 x)^{3}

f (x) = x^{\frac{4}{5}} (x - 2)

y = x e^{\frac{( 5 - x )}{4}}

f (x) = - x^{2} + 3 x + 2

What is the extreme f(x)= 4/3 x^3-13/2 x^2-3x+11 ?
The extreme f(x)= 4/3 x^3-13/2 x^2-3x+11 is