What is the extreme f(x)=2x^2-15x^2+36x+10 ?

The extreme f(x)=2x^2-15x^2+36x+10 is Maximum(18/13 , 454/13)

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extreme f(x)=2x^2-15x^2+36x+10

extreme points

f (x) = 2 x^{2} - 15 x^{2} + 36 x + 10

Maximum (\frac{18}{13}, \frac{454}{13})

Solution steps

f^{'} (x) = - 26 x + 36

Find intervals:

Increasing

: - \infty < x < \frac{18}{13},

Decreasing

: \frac{18}{13} < x < \infty

Plug

x = \frac{18}{13}

into

2 x^{2} - 15 x^{2} + 36 x + 10 : \frac{454}{13}

Maximum (\frac{18}{13}, \frac{454}{13})

\frac{x ^{3}}{x ^{2} - 3}

f (x) = - 7 x^{8} + 3 x^{2} - 4

f (x) = 5 x - 3 x^{2}

y = \frac{x}{x ^{2} + 4}, (- 3, 1)

f (x, y) = 12 x^{2} + 48 x y + 8 y^{3} - 3 y^{4}

What is the extreme f(x)=2x^2-15x^2+36x+10 ?
The extreme f(x)=2x^2-15x^2+36x+10 is Maximum(18/13 , 454/13)